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541075405797313 is a prime number
BaseRepresentation
bin111101100000110101110111…
…1010110111111011111000001
32121221210022012100020110220221
41323001223233112333133001
51031404434412341003223
65154434335424303041
7221653256646463222
oct17301535726773701
92557708170213827
10541075405797313
11147448877847392
1250828056771a81
131a2bb2655c145a
1497882918c9249
15428492dd54b5d
hex1ec1aef5bf7c1

541075405797313 has 2 divisors, whose sum is σ = 541075405797314. Its totient is φ = 541075405797312.

The previous prime is 541075405797229. The next prime is 541075405797347. The reversal of 541075405797313 is 313797504570145.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 503406045370944 + 37669360426369 = 22436712^2 + 6137537^2 .

It is a cyclic number.

It is not a de Polignac number, because 541075405797313 - 217 = 541075405666241 is a prime.

It is not a weakly prime, because it can be changed into another prime (541075405797383) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 270537702898656 + 270537702898657.

It is an arithmetic number, because the mean of its divisors is an integer number (270537702898657).

Almost surely, 2541075405797313 is an apocalyptic number.

It is an amenable number.

541075405797313 is a deficient number, since it is larger than the sum of its proper divisors (1).

541075405797313 is an equidigital number, since it uses as much as digits as its factorization.

541075405797313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 55566000, while the sum is 61.

The spelling of 541075405797313 in words is "five hundred forty-one trillion, seventy-five billion, four hundred five million, seven hundred ninety-seven thousand, three hundred thirteen".