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54110434343 = 7192857142403
BaseRepresentation
bin110010011001001110…
…111011010000100111
312011200001022212111212
4302121032323100213
51341304232344333
640505154222035
73623623050230
oct623116732047
9164601285455
1054110434343
1120a47a25229
12a5a158491b
1351445193b4
1428945d0087
15161a681448
hexc993bb427

54110434343 has 16 divisors (see below), whose sum is σ = 65118501120. Its totient is φ = 43923612096.

The previous prime is 54110434337. The next prime is 54110434351. The reversal of 54110434343 is 34343401145.

It is not a de Polignac number, because 54110434343 - 212 = 54110430247 is a prime.

It is a super-2 number, since 2×541104343432 (a number of 22 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54110434043) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 308780 + ... + 451182.

It is an arithmetic number, because the mean of its divisors is an integer number (4069906320).

Almost surely, 254110434343 is an apocalyptic number.

54110434343 is a deficient number, since it is larger than the sum of its proper divisors (11008066777).

54110434343 is a wasteful number, since it uses less digits than its factorization.

54110434343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 145286.

The product of its (nonzero) digits is 34560, while the sum is 32.

Adding to 54110434343 its reverse (34343401145), we get a palindrome (88453835488).

The spelling of 54110434343 in words is "fifty-four billion, one hundred ten million, four hundred thirty-four thousand, three hundred forty-three".

Divisors: 1 7 19 133 2857 19999 54283 142403 379981 996821 2705657 18939599 406845371 2847917597 7730062049 54110434343