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541130335 = 5108226067
BaseRepresentation
bin100000010000001…
…111111001011111
31101201020021021021
4200100033321133
52102012132320
6125410145011
716260350314
oct4020177137
91351207237
10541130335
112584aa259
12131282167
1388156285
1451c20d0b
153278edaa
hex2040fe5f

541130335 has 4 divisors (see below), whose sum is σ = 649356408. Its totient is φ = 432904264.

The previous prime is 541130321. The next prime is 541130347. The reversal of 541130335 is 533031145.

541130335 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 541130335 - 215 = 541097567 is a prime.

It is a Duffinian number.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 54113029 + ... + 54113038.

It is an arithmetic number, because the mean of its divisors is an integer number (162339102).

Almost surely, 2541130335 is an apocalyptic number.

541130335 is a deficient number, since it is larger than the sum of its proper divisors (108226073).

541130335 is a wasteful number, since it uses less digits than its factorization.

541130335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 108226072.

The product of its (nonzero) digits is 2700, while the sum is 25.

The square root of 541130335 is about 23262.2083001593. The cubic root of 541130335 is about 814.8930744087.

The spelling of 541130335 in words is "five hundred forty-one million, one hundred thirty thousand, three hundred thirty-five".

Divisors: 1 5 108226067 541130335