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54113041153 is a prime number
BaseRepresentation
bin110010011001011000…
…110111101100000001
312011200020020022101101
4302121120313230001
51341310414304103
640505330134401
73623654155243
oct623130675401
9164606208341
1054113041153
1120a49445816
12a5a2421401
135144c1caa2
142894aac093
15161a9e8a1d
hexc99637b01

54113041153 has 2 divisors, whose sum is σ = 54113041154. Its totient is φ = 54113041152.

The previous prime is 54113041141. The next prime is 54113041189. The reversal of 54113041153 is 35114031145.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 37174539249 + 16938501904 = 192807^2 + 130148^2 .

It is a cyclic number.

It is not a de Polignac number, because 54113041153 - 25 = 54113041121 is a prime.

It is not a weakly prime, because it can be changed into another prime (54113041123) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27056520576 + 27056520577.

It is an arithmetic number, because the mean of its divisors is an integer number (27056520577).

Almost surely, 254113041153 is an apocalyptic number.

It is an amenable number.

54113041153 is a deficient number, since it is larger than the sum of its proper divisors (1).

54113041153 is an equidigital number, since it uses as much as digits as its factorization.

54113041153 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3600, while the sum is 28.

Adding to 54113041153 its reverse (35114031145), we get a palindrome (89227072298).

The spelling of 54113041153 in words is "fifty-four billion, one hundred thirteen million, forty-one thousand, one hundred fifty-three".