Base | Representation |
---|---|
bin | 11000100110111010010111… |
… | …00110100011111010000011 |
3 | 21002121012120010120212202021 |
4 | 30103131023212203322003 |
5 | 24043044033202041201 |
6 | 311031232113302311 |
7 | 14253401332163362 |
oct | 1423351346437203 |
9 | 232535503525667 |
10 | 54113561362051 |
11 | 16273483718894 |
12 | 609b6a2264997 |
13 | 2426b6b7bab19 |
14 | d51178add7d9 |
15 | 63c9406e0ea1 |
hex | 31374b9a3e83 |
54113561362051 has 2 divisors, whose sum is σ = 54113561362052. Its totient is φ = 54113561362050.
The previous prime is 54113561362019. The next prime is 54113561362097. The reversal of 54113561362051 is 15026316531145.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 54113561362051 - 25 = 54113561362019 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 54113561361989 and 54113561362007.
It is not a weakly prime, because it can be changed into another prime (54113561362151) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27056780681025 + 27056780681026.
It is an arithmetic number, because the mean of its divisors is an integer number (27056780681026).
Almost surely, 254113561362051 is an apocalyptic number.
54113561362051 is a deficient number, since it is larger than the sum of its proper divisors (1).
54113561362051 is an equidigital number, since it uses as much as digits as its factorization.
54113561362051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324000, while the sum is 43.
Adding to 54113561362051 its reverse (15026316531145), we get a palindrome (69139877893196).
The spelling of 54113561362051 in words is "fifty-four trillion, one hundred thirteen billion, five hundred sixty-one million, three hundred sixty-two thousand, fifty-one".
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