Base | Representation |
---|---|
bin | 11000100110111011010001… |
… | …10111000110101011010001 |
3 | 21002121020211100020222000012 |
4 | 30103131220313012223101 |
5 | 24043101034333104113 |
6 | 311031352530404305 |
7 | 14253416442436604 |
oct | 1423355067065321 |
9 | 232536740228005 |
10 | 54114052238033 |
11 | 16273705813217 |
12 | 609b7ba730695 |
13 | 2426c193c9c98 |
14 | d511c3d9c33b |
15 | 63c96d855aa8 |
hex | 313768dc6ad1 |
54114052238033 has 2 divisors, whose sum is σ = 54114052238034. Its totient is φ = 54114052238032.
The previous prime is 54114052238017. The next prime is 54114052238053. The reversal of 54114052238033 is 33083225041145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52095655223824 + 2018397014209 = 7217732^2 + 1420703^2 .
It is a cyclic number.
It is not a de Polignac number, because 54114052238033 - 24 = 54114052238017 is a prime.
It is not a weakly prime, because it can be changed into another prime (54114052238053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27057026119016 + 27057026119017.
It is an arithmetic number, because the mean of its divisors is an integer number (27057026119017).
Almost surely, 254114052238033 is an apocalyptic number.
It is an amenable number.
54114052238033 is a deficient number, since it is larger than the sum of its proper divisors (1).
54114052238033 is an equidigital number, since it uses as much as digits as its factorization.
54114052238033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 345600, while the sum is 41.
Adding to 54114052238033 its reverse (33083225041145), we get a palindrome (87197277279178).
The spelling of 54114052238033 in words is "fifty-four trillion, one hundred fourteen billion, fifty-two million, two hundred thirty-eight thousand, thirty-three".
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