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5411501325121 is a prime number
BaseRepresentation
bin100111010111111011010…
…0111010011101101000001
3201011100000211110100102111
41032233312213103231001
51202130223314400441
615302002010015321
71065653022212233
oct116576647235501
921140024410374
105411501325121
1117a7006469731
12734950a17541
133033c1457218
14149cbd238253
1595b73bd5081
hex4ebf69d3b41

5411501325121 has 2 divisors, whose sum is σ = 5411501325122. Its totient is φ = 5411501325120.

The previous prime is 5411501325091. The next prime is 5411501325143. The reversal of 5411501325121 is 1215231051145.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3568868831025 + 1842632494096 = 1889145^2 + 1357436^2 .

It is a cyclic number.

It is not a de Polignac number, because 5411501325121 - 223 = 5411492936513 is a prime.

It is not a weakly prime, because it can be changed into another prime (5411501325221) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2705750662560 + 2705750662561.

It is an arithmetic number, because the mean of its divisors is an integer number (2705750662561).

Almost surely, 25411501325121 is an apocalyptic number.

It is an amenable number.

5411501325121 is a deficient number, since it is larger than the sum of its proper divisors (1).

5411501325121 is an equidigital number, since it uses as much as digits as its factorization.

5411501325121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6000, while the sum is 31.

Adding to 5411501325121 its reverse (1215231051145), we get a palindrome (6626732376266).

The spelling of 5411501325121 in words is "five trillion, four hundred eleven billion, five hundred one million, three hundred twenty-five thousand, one hundred twenty-one".