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54117433 is a prime number
BaseRepresentation
bin1100111001110…
…0010000111001
310202211110011101
43032130100321
5102323224213
65211531401
71224663526
oct316342071
9122743141
1054117433
1128603257
1216159b61
13b29a566
14728a14d
154b3ebdd
hex339c439

54117433 has 2 divisors, whose sum is σ = 54117434. Its totient is φ = 54117432.

The previous prime is 54117419. The next prime is 54117457. The reversal of 54117433 is 33471145.

54117433 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 30769209 + 23348224 = 5547^2 + 4832^2 .

It is a cyclic number.

It is not a de Polignac number, because 54117433 - 221 = 52020281 is a prime.

It is not a weakly prime, because it can be changed into another prime (54117403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27058716 + 27058717.

It is an arithmetic number, because the mean of its divisors is an integer number (27058717).

Almost surely, 254117433 is an apocalyptic number.

It is an amenable number.

54117433 is a deficient number, since it is larger than the sum of its proper divisors (1).

54117433 is an equidigital number, since it uses as much as digits as its factorization.

54117433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 5040, while the sum is 28.

The square root of 54117433 is about 7356.4551925503. The cubic root of 54117433 is about 378.2501097560.

Adding to 54117433 its reverse (33471145), we get a palindrome (87588578).

The spelling of 54117433 in words is "fifty-four million, one hundred seventeen thousand, four hundred thirty-three".