Base | Representation |
---|---|
bin | 11000100111001010000101… |
… | …10010100101001101010001 |
3 | 21002122000100110212112002021 |
4 | 30103211002302211031101 |
5 | 24043213330340442003 |
6 | 311035145524451441 |
7 | 14254120461601615 |
oct | 1423450262451521 |
9 | 232560313775067 |
10 | 54122003452753 |
11 | 16277015a9a555 |
12 | 60a1259549b81 |
13 | 24278b57bb872 |
14 | d51739da7345 |
15 | 63cc869162bd |
hex | 313942ca5351 |
54122003452753 has 2 divisors, whose sum is σ = 54122003452754. Its totient is φ = 54122003452752.
The previous prime is 54122003452739. The next prime is 54122003452787. The reversal of 54122003452753 is 35725430022145.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 44371478860864 + 9750524591889 = 6661192^2 + 3122583^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54122003452753 is a prime.
It is not a weakly prime, because it can be changed into another prime (54122003432753) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27061001726376 + 27061001726377.
It is an arithmetic number, because the mean of its divisors is an integer number (27061001726377).
Almost surely, 254122003452753 is an apocalyptic number.
It is an amenable number.
54122003452753 is a deficient number, since it is larger than the sum of its proper divisors (1).
54122003452753 is an equidigital number, since it uses as much as digits as its factorization.
54122003452753 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008000, while the sum is 43.
Adding to 54122003452753 its reverse (35725430022145), we get a palindrome (89847433474898).
The spelling of 54122003452753 in words is "fifty-four trillion, one hundred twenty-two billion, three million, four hundred fifty-two thousand, seven hundred fifty-three".
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