Base | Representation |
---|---|
bin | 100111011000011010001… |
… | …1010000101101000001011 |
3 | 201011102201002020021110122 |
4 | 1032300310122011220023 |
5 | 1202134334220000422 |
6 | 15302252522333455 |
7 | 1066020511206041 |
oct | 116606432055013 |
9 | 21142632207418 |
10 | 5412538046987 |
11 | 17a7498694165 |
12 | 734ba005a28b |
13 | 303528180b06 |
14 | 149d7abc4391 |
15 | 95bd4c1bd42 |
hex | 4ec34685a0b |
5412538046987 has 2 divisors, whose sum is σ = 5412538046988. Its totient is φ = 5412538046986.
The previous prime is 5412538046963. The next prime is 5412538047019. The reversal of 5412538046987 is 7896408352145.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5412538046987 - 220 = 5412536998411 is a prime.
It is a super-2 number, since 2×54125380469872 (a number of 26 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (5412538046957) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2706269023493 + 2706269023494.
It is an arithmetic number, because the mean of its divisors is an integer number (2706269023494).
It is a 2-persistent number, because it is pandigital, and so is 2⋅5412538046987 = 10825076093974, but 3⋅5412538046987 = 16237614140961 is not.
Almost surely, 25412538046987 is an apocalyptic number.
5412538046987 is a deficient number, since it is larger than the sum of its proper divisors (1).
5412538046987 is an equidigital number, since it uses as much as digits as its factorization.
5412538046987 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 58060800, while the sum is 62.
The spelling of 5412538046987 in words is "five trillion, four hundred twelve billion, five hundred thirty-eight million, forty-six thousand, nine hundred eighty-seven".
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