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54129433 is a prime number
BaseRepresentation
bin1100111001111…
…1001100011001
310202212001121211
43032133030121
5102324120213
65212103121
71225043521
oct316371431
9122761554
1054129433
1128611276
1216164aa1
13b2a2b67
147290681
154b4353d
hex339f319

54129433 has 2 divisors, whose sum is σ = 54129434. Its totient is φ = 54129432.

The previous prime is 54129407. The next prime is 54129443. The reversal of 54129433 is 33492145.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 37417689 + 16711744 = 6117^2 + 4088^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-54129433 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 54129395 and 54129404.

It is not a weakly prime, because it can be changed into another prime (54129403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27064716 + 27064717.

It is an arithmetic number, because the mean of its divisors is an integer number (27064717).

Almost surely, 254129433 is an apocalyptic number.

It is an amenable number.

54129433 is a deficient number, since it is larger than the sum of its proper divisors (1).

54129433 is an equidigital number, since it uses as much as digits as its factorization.

54129433 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 12960, while the sum is 31.

The square root of 54129433 is about 7357.2707575568. The cubic root of 54129433 is about 378.2780654172.

The spelling of 54129433 in words is "fifty-four million, one hundred twenty-nine thousand, four hundred thirty-three".