Base | Representation |
---|---|
bin | 100111011000101001001… |
… | …0101011101101001100101 |
3 | 201011111000002000210212210 |
4 | 1032301102111131221211 |
5 | 1202141401234314031 |
6 | 15302414420234033 |
7 | 1066036116055410 |
oct | 116612225355145 |
9 | 21144002023783 |
10 | 5413040151141 |
11 | 17a7726058477 |
12 | 73510023b919 |
13 | 3035a81c186c |
14 | 149dc7766b77 |
15 | 95c13d4d746 |
hex | 4ec5255da65 |
5413040151141 has 16 divisors (see below), whose sum is σ = 8248477952000. Its totient is φ = 3093152369328.
The previous prime is 5413040151091. The next prime is 5413040151157. The reversal of 5413040151141 is 1411510403145.
It is not a de Polignac number, because 5413040151141 - 210 = 5413040150117 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 5413040151099 and 5413040151108.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5413040152141) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 6410640 + ... + 7205718.
It is an arithmetic number, because the mean of its divisors is an integer number (515529872000).
Almost surely, 25413040151141 is an apocalyptic number.
It is an amenable number.
5413040151141 is a deficient number, since it is larger than the sum of its proper divisors (2835437800859).
5413040151141 is a wasteful number, since it uses less digits than its factorization.
5413040151141 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1119288.
The product of its (nonzero) digits is 4800, while the sum is 30.
Adding to 5413040151141 its reverse (1411510403145), we get a palindrome (6824550554286).
The spelling of 5413040151141 in words is "five trillion, four hundred thirteen billion, forty million, one hundred fifty-one thousand, one hundred forty-one".
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