Base | Representation |
---|---|
bin | 11000100111100001000011… |
… | …10000010111010100101010 |
3 | 21002200012011211012120222002 |
4 | 30103300201300113110222 |
5 | 24043414104014002404 |
6 | 311044545245531002 |
7 | 14255035156564460 |
oct | 1423604160272452 |
9 | 232605154176862 |
10 | 54134334125354 |
11 | 1628127337536a |
12 | 60a371ab73a62 |
13 | 2428acc300342 |
14 | d521898a0830 |
15 | 63d259203c1e |
hex | 313c21c1752a |
54134334125354 has 16 divisors (see below), whose sum is σ = 92805335247168. Its totient is φ = 23199524009952.
The previous prime is 54134334125329. The next prime is 54134334125357. The reversal of 54134334125354 is 45352143343145.
It is a super-2 number, since 2×541343341253542 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54134334125299 and 54134334125308.
It is not an unprimeable number, because it can be changed into a prime (54134334125357) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 75036587 + ... + 75754590.
It is an arithmetic number, because the mean of its divisors is an integer number (5800333452948).
Almost surely, 254134334125354 is an apocalyptic number.
54134334125354 is a deficient number, since it is larger than the sum of its proper divisors (38671001121814).
54134334125354 is a wasteful number, since it uses less digits than its factorization.
54134334125354 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 150816829.
The product of its digits is 5184000, while the sum is 47.
Adding to 54134334125354 its reverse (45352143343145), we get a palindrome (99486477468499).
The spelling of 54134334125354 in words is "fifty-four trillion, one hundred thirty-four billion, three hundred thirty-four million, one hundred twenty-five thousand, three hundred fifty-four".
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