Search a number
-
+
5414052444433 is a prime number
BaseRepresentation
bin100111011001000111010…
…1011000011100100010001
3201011120121121211122012221
41032302032223003210101
51202200434411210213
615303103101221041
71066103160316663
oct116621653034421
921146547748187
105414052444433
1117a80a55083a6
12735343261781
13303709b44389
1414a081d94533
1595c72b5c38d
hex4ec8eac3911

5414052444433 has 2 divisors, whose sum is σ = 5414052444434. Its totient is φ = 5414052444432.

The previous prime is 5414052444413. The next prime is 5414052444511. The reversal of 5414052444433 is 3344442504145.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5328119625984 + 85932818449 = 2308272^2 + 293143^2 .

It is a cyclic number.

It is not a de Polignac number, because 5414052444433 - 213 = 5414052436241 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 5414052444433.

It is not a weakly prime, because it can be changed into another prime (5414052444403) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2707026222216 + 2707026222217.

It is an arithmetic number, because the mean of its divisors is an integer number (2707026222217).

Almost surely, 25414052444433 is an apocalyptic number.

It is an amenable number.

5414052444433 is a deficient number, since it is larger than the sum of its proper divisors (1).

5414052444433 is an equidigital number, since it uses as much as digits as its factorization.

5414052444433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1843200, while the sum is 43.

Adding to 5414052444433 its reverse (3344442504145), we get a palindrome (8758494948578).

The spelling of 5414052444433 in words is "five trillion, four hundred fourteen billion, fifty-two million, four hundred forty-four thousand, four hundred thirty-three".