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5414112352003 is a prime number
BaseRepresentation
bin100111011001001001000…
…1111100101011100000011
3201011120202210120020221211
41032302102033211130003
51202201100230231003
615303113041230551
71066104515450425
oct116622217453403
921146683506854
105414112352003
1117a8126305893
1273535b332457
1330371938b244
1414a089d0a815
1595c7804296d
hex4ec923e5703

5414112352003 has 2 divisors, whose sum is σ = 5414112352004. Its totient is φ = 5414112352002.

The previous prime is 5414112351961. The next prime is 5414112352067. The reversal of 5414112352003 is 3002532114145.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 5414112352003 - 217 = 5414112220931 is a prime.

It is a super-3 number, since 3×54141123520033 (a number of 39 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (5414112352603) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2707056176001 + 2707056176002.

It is an arithmetic number, because the mean of its divisors is an integer number (2707056176002).

Almost surely, 25414112352003 is an apocalyptic number.

5414112352003 is a deficient number, since it is larger than the sum of its proper divisors (1).

5414112352003 is an equidigital number, since it uses as much as digits as its factorization.

5414112352003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 14400, while the sum is 31.

Adding to 5414112352003 its reverse (3002532114145), we get a palindrome (8416644466148).

The spelling of 5414112352003 in words is "five trillion, four hundred fourteen billion, one hundred twelve million, three hundred fifty-two thousand, three".