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54141151003 = 531676116953
BaseRepresentation
bin110010011011000100…
…000110011100011011
312011202012010102211221
4302123010012130123
51341340113313003
640512212432511
73624445122202
oct623304063433
9164665112757
1054141151003
1120a632a50a5
12a5ab918737
13514a9b2634
142898708239
15161d1ec7bd
hexc9b10671b

54141151003 has 8 divisors (see below), whose sum is σ = 55493006688. Its totient is φ = 52801529664.

The previous prime is 54141150983. The next prime is 54141151069. The reversal of 54141151003 is 30015114145.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 54141151003 - 229 = 53604280091 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (54141151403) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 3049626 + ... + 3067327.

It is an arithmetic number, because the mean of its divisors is an integer number (6936625836).

Almost surely, 254141151003 is an apocalyptic number.

54141151003 is a gapful number since it is divisible by the number (53) formed by its first and last digit.

54141151003 is a deficient number, since it is larger than the sum of its proper divisors (1351855685).

54141151003 is a wasteful number, since it uses less digits than its factorization.

54141151003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6117173.

The product of its (nonzero) digits is 1200, while the sum is 25.

Adding to 54141151003 its reverse (30015114145), we get a palindrome (84156265148).

The spelling of 54141151003 in words is "fifty-four billion, one hundred forty-one million, one hundred fifty-one thousand, three".

Divisors: 1 53 167 8851 6116953 324198509 1021531151 54141151003