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5414943403 is a prime number
BaseRepresentation
bin1010000101100000…
…10111101010101011
3111222101011121220101
411002300113222223
542042211142103
62253153010231
7251121155002
oct50260275253
914871147811
105414943403
11232965a141
121071553977
13683b02b2c
14395235c39
1521a5bca1d
hex142c17aab

5414943403 has 2 divisors, whose sum is σ = 5414943404. Its totient is φ = 5414943402.

The previous prime is 5414943319. The next prime is 5414943421. The reversal of 5414943403 is 3043494145.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5414943403 - 29 = 5414942891 is a prime.

It is a super-2 number, since 2×54149434032 = 58643224115386440818, which contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (5414943433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2707471701 + 2707471702.

It is an arithmetic number, because the mean of its divisors is an integer number (2707471702).

Almost surely, 25414943403 is an apocalyptic number.

5414943403 is a deficient number, since it is larger than the sum of its proper divisors (1).

5414943403 is an equidigital number, since it uses as much as digits as its factorization.

5414943403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 37.

The square root of 5414943403 is about 73586.2990168686. The cubic root of 5414943403 is about 1756.0274774396.

The spelling of 5414943403 in words is "five billion, four hundred fourteen million, nine hundred forty-three thousand, four hundred three".