Base | Representation |
---|---|
bin | 110010011011101101… |
… | …111111001000101011 |
3 | 12011202221210021201202 |
4 | 302123231333020223 |
5 | 1341400421143430 |
6 | 40513244034415 |
7 | 3624640343165 |
oct | 623355771053 |
9 | 164687707652 |
10 | 54152131115 |
11 | 20a69514675 |
12 | a5b3532a0b |
13 | 5150058344 |
14 | 2899d65935 |
15 | 161e16ad45 |
hex | c9bb7f22b |
54152131115 has 4 divisors (see below), whose sum is σ = 64982557344. Its totient is φ = 43321704888.
The previous prime is 54152131073. The next prime is 54152131123. The reversal of 54152131115 is 51113125145.
It is a happy number.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 54152131115 - 222 = 54147936811 is a prime.
It is a super-3 number, since 3×541521311153 (a number of 33 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Duffinian number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5415213107 + ... + 5415213116.
It is an arithmetic number, because the mean of its divisors is an integer number (16245639336).
Almost surely, 254152131115 is an apocalyptic number.
54152131115 is a deficient number, since it is larger than the sum of its proper divisors (10830426229).
54152131115 is a wasteful number, since it uses less digits than its factorization.
54152131115 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10830426228.
The product of its digits is 3000, while the sum is 29.
The spelling of 54152131115 in words is "fifty-four billion, one hundred fifty-two million, one hundred thirty-one thousand, one hundred fifteen".
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