Base | Representation |
---|---|
bin | 110010011011101101… |
… | …111111001000110011 |
3 | 12011202221210021202001 |
4 | 302123231333020303 |
5 | 1341400421143443 |
6 | 40513244034431 |
7 | 3624640343206 |
oct | 623355771063 |
9 | 164687707661 |
10 | 54152131123 |
11 | 20a69514682 |
12 | a5b3532a17 |
13 | 515005834c |
14 | 2899d6593d |
15 | 161e16ad4d |
hex | c9bb7f233 |
54152131123 has 2 divisors, whose sum is σ = 54152131124. Its totient is φ = 54152131122.
The previous prime is 54152131073. The next prime is 54152131133. The reversal of 54152131123 is 32113125145.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 54152131123 - 217 = 54152000051 is a prime.
It is a super-2 number, since 2×541521311232 (a number of 22 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54152131091 and 54152131100.
It is not a weakly prime, because it can be changed into another prime (54152131133) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27076065561 + 27076065562.
It is an arithmetic number, because the mean of its divisors is an integer number (27076065562).
Almost surely, 254152131123 is an apocalyptic number.
54152131123 is a deficient number, since it is larger than the sum of its proper divisors (1).
54152131123 is an equidigital number, since it uses as much as digits as its factorization.
54152131123 is an evil number, because the sum of its binary digits is even.
The product of its digits is 3600, while the sum is 28.
Adding to 54152131123 its reverse (32113125145), we get a palindrome (86265256268).
The spelling of 54152131123 in words is "fifty-four billion, one hundred fifty-two million, one hundred thirty-one thousand, one hundred twenty-three".
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