Base | Representation |
---|---|
bin | 110010011110101100… |
… | …101001110001011001 |
3 | 12011220102211122010212 |
4 | 302132230221301121 |
5 | 1342001220104423 |
6 | 40522231220505 |
7 | 3626115234251 |
oct | 623654516131 |
9 | 164812748125 |
10 | 54202113113 |
11 | 20a94752905 |
12 | a608217735 |
13 | 515a5084a5 |
14 | 28a2856961 |
15 | 1623740578 |
hex | c9eb29c59 |
54202113113 has 2 divisors, whose sum is σ = 54202113114. Its totient is φ = 54202113112.
The previous prime is 54202113059. The next prime is 54202113139. The reversal of 54202113113 is 31131120245.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 29593288729 + 24608824384 = 172027^2 + 156872^2 .
It is a cyclic number.
It is not a de Polignac number, because 54202113113 - 28 = 54202112857 is a prime.
It is not a weakly prime, because it can be changed into another prime (54202113313) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27101056556 + 27101056557.
It is an arithmetic number, because the mean of its divisors is an integer number (27101056557).
Almost surely, 254202113113 is an apocalyptic number.
It is an amenable number.
54202113113 is a deficient number, since it is larger than the sum of its proper divisors (1).
54202113113 is an equidigital number, since it uses as much as digits as its factorization.
54202113113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 720, while the sum is 23.
Adding to 54202113113 its reverse (31131120245), we get a palindrome (85333233358).
The spelling of 54202113113 in words is "fifty-four billion, two hundred two million, one hundred thirteen thousand, one hundred thirteen".
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