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54204213213233 is a prime number
BaseRepresentation
bin11000101001100011001101…
…10111111011100000110001
321002220212112211001001120222
430110301212313323200301
524101040212040310413
6311141023301142425
714263060635203606
oct1424614667734061
9232825484031528
1054204213213233
11162a8972292366
1260b51813baa15
132432587691855
14d556d84006ad
1563ee98dcdb08
hex314c66dfb831

54204213213233 has 2 divisors, whose sum is σ = 54204213213234. Its totient is φ = 54204213213232.

The previous prime is 54204213213217. The next prime is 54204213213257. The reversal of 54204213213233 is 33231231240245.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 49933613242384 + 4270599970849 = 7066372^2 + 2066543^2 .

It is a cyclic number.

It is not a de Polignac number, because 54204213213233 - 24 = 54204213213217 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 54204213213193 and 54204213213202.

It is not a weakly prime, because it can be changed into another prime (54204213213203) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27102106606616 + 27102106606617.

It is an arithmetic number, because the mean of its divisors is an integer number (27102106606617).

Almost surely, 254204213213233 is an apocalyptic number.

It is an amenable number.

54204213213233 is a deficient number, since it is larger than the sum of its proper divisors (1).

54204213213233 is an equidigital number, since it uses as much as digits as its factorization.

54204213213233 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 103680, while the sum is 35.

Adding to 54204213213233 its reverse (33231231240245), we get a palindrome (87435444453478).

The spelling of 54204213213233 in words is "fifty-four trillion, two hundred four billion, two hundred thirteen million, two hundred thirteen thousand, two hundred thirty-three".