Base | Representation |
---|---|
bin | 100111011100000101110… |
… | …0011001110101010011111 |
3 | 201012012002221212201001020 |
4 | 1032320023203032222133 |
5 | 1202302031240341111 |
6 | 15310041130415223 |
7 | 1066420422101451 |
oct | 116701343165237 |
9 | 21165087781036 |
10 | 5420442512031 |
11 | 17aa88453a7a8 |
12 | 736627291513 |
13 | 3041b7984871 |
14 | 14a4ca9002d1 |
15 | 95ee8b45906 |
hex | 4ee0b8cea9f |
5420442512031 has 16 divisors (see below), whose sum is σ = 7407713585664. Its totient is φ = 3524216437664.
The previous prime is 5420442511963. The next prime is 5420442512033. The reversal of 5420442512031 is 1302152440245.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5420442512031 is a prime.
It is a super-2 number, since 2×54204425120312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5420442511983 and 5420442512001.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (5420442512033) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 102041811 + ... + 102094916.
It is an arithmetic number, because the mean of its divisors is an integer number (462982099104).
Almost surely, 25420442512031 is an apocalyptic number.
5420442512031 is a deficient number, since it is larger than the sum of its proper divisors (1987271073633).
5420442512031 is a wasteful number, since it uses less digits than its factorization.
5420442512031 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 204136950.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 5420442512031 its reverse (1302152440245), we get a palindrome (6722594952276).
The spelling of 5420442512031 in words is "five trillion, four hundred twenty billion, four hundred forty-two million, five hundred twelve thousand, thirty-one".
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