Base | Representation |
---|---|
bin | 111101100111111100111000… |
… | …0001001111100100110101111 |
3 | 2122002020201022101221001221101 |
4 | 1323033321300021330212233 |
5 | 1032021442032144332303 |
6 | 5200503254131143531 |
7 | 222114000602132665 |
oct | 17317716011744657 |
9 | 2562221271831841 |
10 | 542052524214703 |
11 | 147795203703627 |
12 | 509654b1744ba7 |
13 | 1a35c4451bc5a8 |
14 | 97bd6a706ac35 |
15 | 42a006b89cd1d |
hex | 1ecfe7027c9af |
542052524214703 has 8 divisors (see below), whose sum is σ = 565011586356272. Its totient is φ = 519530777542656.
The previous prime is 542052524214673. The next prime is 542052524214743. The reversal of 542052524214703 is 307412425250245.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-542052524214703 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (542052524214743) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 109328864850 + ... + 109328869807.
It is an arithmetic number, because the mean of its divisors is an integer number (70626448294534).
Almost surely, 2542052524214703 is an apocalyptic number.
542052524214703 is a deficient number, since it is larger than the sum of its proper divisors (22959062141569).
542052524214703 is a wasteful number, since it uses less digits than its factorization.
542052524214703 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 218657734761.
The product of its (nonzero) digits is 2688000, while the sum is 46.
Adding to 542052524214703 its reverse (307412425250245), we get a palindrome (849464949464948).
The spelling of 542052524214703 in words is "five hundred forty-two trillion, fifty-two billion, five hundred twenty-four million, two hundred fourteen thousand, seven hundred three".
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