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542052524214743 is a prime number
BaseRepresentation
bin111101100111111100111000…
…0001001111100100111010111
32122002020201022101221001222212
41323033321300021330213113
51032021442032144332433
65200503254131144035
7222114000602133053
oct17317716011744727
92562221271831885
10542052524214743
11147795203703663
12509654b174501b
131a35c4451bc609
1497bd6a706ac63
1542a006b89cd48
hex1ecfe7027c9d7

542052524214743 has 2 divisors, whose sum is σ = 542052524214744. Its totient is φ = 542052524214742.

The previous prime is 542052524214673. The next prime is 542052524214769. The reversal of 542052524214743 is 347412425250245.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 542052524214743 - 214 = 542052524198359 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 542052524214691 and 542052524214700.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (542052524214793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271026262107371 + 271026262107372.

It is an arithmetic number, because the mean of its divisors is an integer number (271026262107372).

Almost surely, 2542052524214743 is an apocalyptic number.

542052524214743 is a deficient number, since it is larger than the sum of its proper divisors (1).

542052524214743 is an equidigital number, since it uses as much as digits as its factorization.

542052524214743 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10752000, while the sum is 50.

Adding to 542052524214743 its reverse (347412425250245), we get a palindrome (889464949464988).

The spelling of 542052524214743 in words is "five hundred forty-two trillion, fifty-two billion, five hundred twenty-four million, two hundred fourteen thousand, seven hundred forty-three".