Base | Representation |
---|---|
bin | 111101101000011001000010… |
… | …1000111010111010010001111 |
3 | 2122002110111102102221200111212 |
4 | 1323100302011013113102033 |
5 | 1032023434413340314411 |
6 | 5200551135425005035 |
7 | 222121241433546605 |
oct | 17320620507272217 |
9 | 2562414372850455 |
10 | 542113005401231 |
11 | 14780891a768200 |
12 | 5097517078377b |
13 | 1a365063545524 |
14 | 97c25a37b9875 |
15 | 42a190b49e68b |
hex | 1ed0c851d748f |
542113005401231 has 12 divisors (see below), whose sum is σ = 595880006001000. Its totient is φ = 492826922150640.
The previous prime is 542113005401203. The next prime is 542113005401267. The reversal of 542113005401231 is 132104500311245.
It is a de Polignac number, because none of the positive numbers 2k-542113005401231 is a prime.
It is a super-2 number, since 2×5421130054012312 (a number of 30 digits) contains 22 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (542113005451231) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 5523320 + ... + 33387618.
It is an arithmetic number, because the mean of its divisors is an integer number (49656667166750).
Almost surely, 2542113005401231 is an apocalyptic number.
542113005401231 is a deficient number, since it is larger than the sum of its proper divisors (53767000599769).
542113005401231 is a wasteful number, since it uses less digits than its factorization.
542113005401231 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 28025110 (or 28025099 counting only the distinct ones).
The product of its (nonzero) digits is 14400, while the sum is 32.
Adding to 542113005401231 its reverse (132104500311245), we get a palindrome (674217505712476).
The spelling of 542113005401231 in words is "five hundred forty-two trillion, one hundred thirteen billion, five million, four hundred one thousand, two hundred thirty-one".
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