Base | Representation |
---|---|
bin | 11000101001110010001101… |
… | …11001010001101101111001 |
3 | 21002221122100001222000112101 |
4 | 30110321012321101231321 |
5 | 24101203210224130014 |
6 | 311144434345543401 |
7 | 14263464335132035 |
oct | 1424710671215571 |
9 | 232848301860471 |
10 | 54212266630009 |
11 | 16301325224604 |
12 | 60b684a4a4b61 |
13 | 243326bcb8317 |
14 | d55c5dc111c5 |
15 | 6402bae2b474 |
hex | 314e46e51b79 |
54212266630009 has 2 divisors, whose sum is σ = 54212266630010. Its totient is φ = 54212266630008.
The previous prime is 54212266630003. The next prime is 54212266630021. The reversal of 54212266630009 is 90003666221245.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 52620922224784 + 1591344405225 = 7254028^2 + 1261485^2 .
It is a cyclic number.
It is not a de Polignac number, because 54212266630009 - 25 = 54212266629977 is a prime.
It is not a weakly prime, because it can be changed into another prime (54212266630003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27106133315004 + 27106133315005.
It is an arithmetic number, because the mean of its divisors is an integer number (27106133315005).
Almost surely, 254212266630009 is an apocalyptic number.
It is an amenable number.
54212266630009 is a deficient number, since it is larger than the sum of its proper divisors (1).
54212266630009 is an equidigital number, since it uses as much as digits as its factorization.
54212266630009 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 933120, while the sum is 46.
The spelling of 54212266630009 in words is "fifty-four trillion, two hundred twelve billion, two hundred sixty-six million, six hundred thirty thousand, nine".
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