Base | Representation |
---|---|
bin | 111101101000011110101011… |
… | …1001101000001111000111011 |
3 | 2122002111122200201202220202201 |
4 | 1323100331113031001320323 |
5 | 1032024134221212131121 |
6 | 5201000501511411031 |
7 | 222122150566341652 |
oct | 17320752715017073 |
9 | 2562448621686681 |
10 | 542125120036411 |
11 | 147812a770a699a |
12 | 50977591983a77 |
13 | 1a366244376102 |
14 | 97c2dd2718199 |
15 | 42a1db9d15e91 |
hex | 1ed0f57341e3b |
542125120036411 has 2 divisors, whose sum is σ = 542125120036412. Its totient is φ = 542125120036410.
The previous prime is 542125120036399. The next prime is 542125120036427. The reversal of 542125120036411 is 114630021521245.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-542125120036411 is a prime.
It is not a weakly prime, because it can be changed into another prime (542125120036471) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271062560018205 + 271062560018206.
It is an arithmetic number, because the mean of its divisors is an integer number (271062560018206).
Almost surely, 2542125120036411 is an apocalyptic number.
542125120036411 is a deficient number, since it is larger than the sum of its proper divisors (1).
542125120036411 is an equidigital number, since it uses as much as digits as its factorization.
542125120036411 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 57600, while the sum is 37.
Adding to 542125120036411 its reverse (114630021521245), we get a palindrome (656755141557656).
The spelling of 542125120036411 in words is "five hundred forty-two trillion, one hundred twenty-five billion, one hundred twenty million, thirty-six thousand, four hundred eleven".
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