Base | Representation |
---|---|
bin | 1111110001110011000… |
… | …10001001001101101101 |
3 | 1220211100001100221012212 |
4 | 13320321202021031231 |
5 | 32340241032144440 |
6 | 1053015051340205 |
7 | 54111341403644 |
oct | 7707142111555 |
9 | 1824301327185 |
10 | 542131131245 |
11 | 199a09987a30 |
12 | 8909a751665 |
13 | 3c17989b032 |
14 | 1c34c86235b |
15 | e17e781465 |
hex | 7e3988936d |
542131131245 has 32 divisors (see below), whose sum is σ = 711273038976. Its totient is φ = 393403392000.
The previous prime is 542131131239. The next prime is 542131131247.
542131131245 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 542131131245 - 218 = 542130869101 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (542131131247) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 128556377 + ... + 128560593.
It is an arithmetic number, because the mean of its divisors is an integer number (22227282468).
Almost surely, 2542131131245 is an apocalyptic number.
542131131245 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
542131131245 is a deficient number, since it is larger than the sum of its proper divisors (169141907731).
542131131245 is a wasteful number, since it uses less digits than its factorization.
542131131245 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8861.
The product of its digits is 14400, while the sum is 32.
It can be divided in two parts, 542131 and 131245, that added together give a palindrome (673376).
The spelling of 542131131245 in words is "five hundred forty-two billion, one hundred thirty-one million, one hundred thirty-one thousand, two hundred forty-five".
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