Search a number
-
+
5422113413335 = 51084422682667
BaseRepresentation
bin100111011100110111100…
…1001001101100011010111
3201012100102101222021201201
41032321233021031203113
51202313442013211320
615310515015533331
71066510011401023
oct116715711154327
921170371867651
105422113413335
111800561738673
12736a1298a247
133043c2bb3468
1414a6087ad383
159609569c70a
hex4ee6f24d8d7

5422113413335 has 4 divisors (see below), whose sum is σ = 6506536096008. Its totient is φ = 4337690730664.

The previous prime is 5422113413317. The next prime is 5422113413341. The reversal of 5422113413335 is 5333143112245.

It is a happy number.

5422113413335 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 5422113413335 - 213 = 5422113405143 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 5422113413294 and 5422113413303.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 542211341329 + ... + 542211341338.

It is an arithmetic number, because the mean of its divisors is an integer number (1626634024002).

Almost surely, 25422113413335 is an apocalyptic number.

5422113413335 is a deficient number, since it is larger than the sum of its proper divisors (1084422682673).

5422113413335 is a wasteful number, since it uses less digits than its factorization.

5422113413335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1084422682672.

The product of its digits is 129600, while the sum is 37.

The spelling of 5422113413335 in words is "five trillion, four hundred twenty-two billion, one hundred thirteen million, four hundred thirteen thousand, three hundred thirty-five".

Divisors: 1 5 1084422682667 5422113413335