Base | Representation |
---|---|
bin | 11000101010011001011010… |
… | …10000011100101101111101 |
3 | 21010000122122201021201012120 |
4 | 30111030231100130231331 |
5 | 24102024310200130440 |
6 | 311202234514553153 |
7 | 14265141004144002 |
oct | 1425145520345575 |
9 | 233018581251176 |
10 | 54233311333245 |
11 | 1630a24442a630 |
12 | 60ba9422987b9 |
13 | 2435243c52645 |
14 | d56c98b5d8a9 |
15 | 640aed758dd0 |
hex | 31532d41cb7d |
54233311333245 has 32 divisors (see below), whose sum is σ = 97925979093120. Its totient is φ = 25388216797440.
The previous prime is 54233311333237. The next prime is 54233311333277.
54233311333245 is nontrivially palindromic in base 10.
It is not a de Polignac number, because 54233311333245 - 23 = 54233311333237 is a prime.
It is a Curzon number.
It is a junction number, because it is equal to n+sod(n) for n = 54233311333197 and 54233311333206.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 5667007894 + ... + 5667017463.
It is an arithmetic number, because the mean of its divisors is an integer number (3060186846660).
Almost surely, 254233311333245 is an apocalyptic number.
54233311333245 is a gapful number since it is divisible by the number (55) formed by its first and last digit.
It is an amenable number.
54233311333245 is a deficient number, since it is larger than the sum of its proper divisors (43692667759875).
54233311333245 is a wasteful number, since it uses less digits than its factorization.
54233311333245 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11334025405.
The product of its digits is 1166400, while the sum is 42.
It can be divided in two parts, 5423331 and 1333245, that added together give a palindrome (6756576).
The spelling of 54233311333245 in words is "fifty-four trillion, two hundred thirty-three billion, three hundred eleven million, three hundred thirty-three thousand, two hundred forty-five".
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