Base | Representation |
---|---|
bin | 1111110010001110111… |
… | …10010101110001010001 |
3 | 1220211221100110110120122 |
4 | 13321013132111301101 |
5 | 32341230420440441 |
6 | 1053054204320025 |
7 | 54120211364066 |
oct | 7710736256121 |
9 | 1824840413518 |
10 | 542365015121 |
11 | 19a019a03396 |
12 | 89144b43015 |
13 | 3c1b618a067 |
14 | 1c371944c6d |
15 | e19508034b |
hex | 7e47795c51 |
542365015121 has 2 divisors, whose sum is σ = 542365015122. Its totient is φ = 542365015120.
The previous prime is 542365015111. The next prime is 542365015133. The reversal of 542365015121 is 121510563245.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 360834483025 + 181530532096 = 600695^2 + 426064^2 .
It is a cyclic number.
It is not a de Polignac number, because 542365015121 - 218 = 542364752977 is a prime.
It is not a weakly prime, because it can be changed into another prime (542365015111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271182507560 + 271182507561.
It is an arithmetic number, because the mean of its divisors is an integer number (271182507561).
Almost surely, 2542365015121 is an apocalyptic number.
It is an amenable number.
542365015121 is a deficient number, since it is larger than the sum of its proper divisors (1).
542365015121 is an equidigital number, since it uses as much as digits as its factorization.
542365015121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 36000, while the sum is 35.
Adding to 542365015121 its reverse (121510563245), we get a palindrome (663875578366).
The spelling of 542365015121 in words is "five hundred forty-two billion, three hundred sixty-five million, fifteen thousand, one hundred twenty-one".
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