Base | Representation |
---|---|
bin | 11000101010100110010000… |
… | …00000010100010001100011 |
3 | 21010001022102222022021220020 |
4 | 30111103020000110101203 |
5 | 24102132413322241011 |
6 | 311205334405244523 |
7 | 14265503532346116 |
oct | 1425231000242143 |
9 | 233038388267806 |
10 | 54240202540131 |
11 | 16312160327333 |
12 | 6100146103743 |
13 | 2435aa185665a |
14 | d5735007a57d |
15 | 640da3733006 |
hex | 3154c8014463 |
54240202540131 has 32 divisors (see below), whose sum is σ = 75624854100480. Its totient is φ = 34555669234944.
The previous prime is 54240202540127. The next prime is 54240202540163. The reversal of 54240202540131 is 13104520204245.
It is not a de Polignac number, because 54240202540131 - 22 = 54240202540127 is a prime.
It is a super-2 number, since 2×542402025401312 (a number of 28 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 54240202540092 and 54240202540101.
It is not an unprimeable number, because it can be changed into a prime (54240202540031) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 27656055 + ... + 29552288.
It is an arithmetic number, because the mean of its divisors is an integer number (2363276690640).
Almost surely, 254240202540131 is an apocalyptic number.
54240202540131 is a deficient number, since it is larger than the sum of its proper divisors (21384651560349).
54240202540131 is a wasteful number, since it uses less digits than its factorization.
54240202540131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 57208555.
The product of its (nonzero) digits is 38400, while the sum is 33.
Adding to 54240202540131 its reverse (13104520204245), we get a palindrome (67344722744376).
The spelling of 54240202540131 in words is "fifty-four trillion, two hundred forty billion, two hundred two million, five hundred forty thousand, one hundred thirty-one".
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