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54242103301 = 139390230959
BaseRepresentation
bin110010100001000101…
…001101000000000101
312012000020002100100221
4302201011031000011
51342041434301201
640530220304341
73630112161601
oct624105150005
9165006070327
1054242103301
1121005287051
12a6196a20b1
13516589a719
1428a7ca6501
151626ede4a1
hexca114d005

54242103301 has 4 divisors (see below), whose sum is σ = 54632334400. Its totient is φ = 53851872204.

The previous prime is 54242103299. The next prime is 54242103323. The reversal of 54242103301 is 10330124245.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 54242103301 - 21 = 54242103299 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54242803301) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 195115341 + ... + 195115618.

It is an arithmetic number, because the mean of its divisors is an integer number (13658083600).

Almost surely, 254242103301 is an apocalyptic number.

It is an amenable number.

54242103301 is a deficient number, since it is larger than the sum of its proper divisors (390231099).

54242103301 is a wasteful number, since it uses less digits than its factorization.

54242103301 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 390231098.

The product of its (nonzero) digits is 2880, while the sum is 25.

Adding to 54242103301 its reverse (10330124245), we get a palindrome (64572227546).

The spelling of 54242103301 in words is "fifty-four billion, two hundred forty-two million, one hundred three thousand, three hundred one".

Divisors: 1 139 390230959 54242103301