Base | Representation |
---|---|
bin | 1111110010010101110… |
… | …00010001101001100001 |
3 | 1220212002022221222220112 |
4 | 13321022320101221201 |
5 | 32341340032130013 |
6 | 1053104005021105 |
7 | 54121504110254 |
oct | 7711270215141 |
9 | 1825068858815 |
10 | 542422145633 |
11 | 19a049184395 |
12 | 891600b4795 |
13 | 3c1c4c70bb4 |
14 | 1c37937709b |
15 | e19a0b7ba8 |
hex | 7e4ae11a61 |
542422145633 has 2 divisors, whose sum is σ = 542422145634. Its totient is φ = 542422145632.
The previous prime is 542422145621. The next prime is 542422145689. The reversal of 542422145633 is 336541224245.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 542000746849 + 421398784 = 736207^2 + 20528^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-542422145633 is a prime.
It is not a weakly prime, because it can be changed into another prime (542422145693) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271211072816 + 271211072817.
It is an arithmetic number, because the mean of its divisors is an integer number (271211072817).
Almost surely, 2542422145633 is an apocalyptic number.
It is an amenable number.
542422145633 is a deficient number, since it is larger than the sum of its proper divisors (1).
542422145633 is an equidigital number, since it uses as much as digits as its factorization.
542422145633 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 691200, while the sum is 41.
Adding to 542422145633 its reverse (336541224245), we get a palindrome (878963369878).
The spelling of 542422145633 in words is "five hundred forty-two billion, four hundred twenty-two million, one hundred forty-five thousand, six hundred thirty-three".
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