Base | Representation |
---|---|
bin | 111101101010101010100001… |
… | …1001001101000011001111001 |
3 | 2122010120100211221102101100002 |
4 | 1323111111003021220121321 |
5 | 1032044044240403440433 |
6 | 5201350445244322345 |
7 | 222152641564145315 |
oct | 17325250311503171 |
9 | 2563510757371302 |
10 | 542425431311993 |
11 | 147919373a79139 |
12 | 50a058235433b5 |
13 | 1a38866381cb48 |
14 | 97d3760d26b45 |
15 | 42a9ae49ae9e8 |
hex | 1ed5543268679 |
542425431311993 has 2 divisors, whose sum is σ = 542425431311994. Its totient is φ = 542425431311992.
The previous prime is 542425431311977. The next prime is 542425431312113. The reversal of 542425431311993 is 399113134524245.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 542425404240784 + 27071209 = 23290028^2 + 5203^2 .
It is a cyclic number.
It is not a de Polignac number, because 542425431311993 - 24 = 542425431311977 is a prime.
It is not a weakly prime, because it can be changed into another prime (542425431311923) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271212715655996 + 271212715655997.
It is an arithmetic number, because the mean of its divisors is an integer number (271212715655997).
Almost surely, 2542425431311993 is an apocalyptic number.
It is an amenable number.
542425431311993 is a deficient number, since it is larger than the sum of its proper divisors (1).
542425431311993 is an equidigital number, since it uses as much as digits as its factorization.
542425431311993 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 13996800, while the sum is 56.
The spelling of 542425431311993 in words is "five hundred forty-two trillion, four hundred twenty-five billion, four hundred thirty-one million, three hundred eleven thousand, nine hundred ninety-three".
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