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542433105953 is a prime number
BaseRepresentation
bin1111110010010111000…
…10000101100000100001
31220212010002120211122022
413321023202011200201
532341400333342303
61053105035551225
754121666216454
oct7711342054041
91825102524568
10542433105953
1119a054390002
12891638bb515
133c1c730a8ab
141c37a9cb49b
15e19b030438
hex7e4b885821

542433105953 has 2 divisors, whose sum is σ = 542433105954. Its totient is φ = 542433105952.

The previous prime is 542433105947. The next prime is 542433106021. The reversal of 542433105953 is 359501334245.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 312428456209 + 230004649744 = 558953^2 + 479588^2 .

It is a cyclic number.

It is not a de Polignac number, because 542433105953 - 26 = 542433105889 is a prime.

It is not a weakly prime, because it can be changed into another prime (542433105653) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 271216552976 + 271216552977.

It is an arithmetic number, because the mean of its divisors is an integer number (271216552977).

Almost surely, 2542433105953 is an apocalyptic number.

It is an amenable number.

542433105953 is a deficient number, since it is larger than the sum of its proper divisors (1).

542433105953 is an equidigital number, since it uses as much as digits as its factorization.

542433105953 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 972000, while the sum is 44.

The spelling of 542433105953 in words is "five hundred forty-two billion, four hundred thirty-three million, one hundred five thousand, nine hundred fifty-three".