Base | Representation |
---|---|
bin | 100111011110010100100… |
… | …0101111111001111001001 |
3 | 201012122110211021100001201 |
4 | 1032330221011333033021 |
5 | 1202341334140133231 |
6 | 15312152342144201 |
7 | 1066650222506125 |
oct | 116745105771711 |
9 | 21178424240051 |
10 | 5425233130441 |
11 | 1801912737273 |
12 | 737543722061 |
13 | 30479c322c07 |
14 | 14a822c5a585 |
15 | 961c94dd161 |
hex | 4ef2917f3c9 |
5425233130441 has 2 divisors, whose sum is σ = 5425233130442. Its totient is φ = 5425233130440.
The previous prime is 5425233130399. The next prime is 5425233130451. The reversal of 5425233130441 is 1440313325245.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 5381954569216 + 43278561225 = 2319904^2 + 208035^2 .
It is a cyclic number.
It is not a de Polignac number, because 5425233130441 - 27 = 5425233130313 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 5425233130441.
It is not a weakly prime, because it can be changed into another prime (5425233130451) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2712616565220 + 2712616565221.
It is an arithmetic number, because the mean of its divisors is an integer number (2712616565221).
Almost surely, 25425233130441 is an apocalyptic number.
It is an amenable number.
5425233130441 is a deficient number, since it is larger than the sum of its proper divisors (1).
5425233130441 is an equidigital number, since it uses as much as digits as its factorization.
5425233130441 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 172800, while the sum is 37.
Adding to 5425233130441 its reverse (1440313325245), we get a palindrome (6865546455686).
The spelling of 5425233130441 in words is "five trillion, four hundred twenty-five billion, two hundred thirty-three million, one hundred thirty thousand, four hundred forty-one".
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