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5425301414257 is a prime number
BaseRepresentation
bin100111011110010110100…
…1010011110000101110001
3201012122122120202111211221
41032330231022132011301
51202342004130224012
615312203221505041
71066652012064244
oct116745512360561
921178576674757
105425301414257
11180194823597a
12737562572181
133047b051053a
1414a82bd5325b
15961d04ca507
hex4ef2d29e171

5425301414257 has 2 divisors, whose sum is σ = 5425301414258. Its totient is φ = 5425301414256.

The previous prime is 5425301414227. The next prime is 5425301414263. The reversal of 5425301414257 is 7524141035245.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3694837462416 + 1730463951841 = 1922196^2 + 1315471^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-5425301414257 is a prime.

It is a super-3 number, since 3×54253014142573 (a number of 39 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (5425301414227) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2712650707128 + 2712650707129.

It is an arithmetic number, because the mean of its divisors is an integer number (2712650707129).

Almost surely, 25425301414257 is an apocalyptic number.

It is an amenable number.

5425301414257 is a deficient number, since it is larger than the sum of its proper divisors (1).

5425301414257 is an equidigital number, since it uses as much as digits as its factorization.

5425301414257 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 672000, while the sum is 43.

The spelling of 5425301414257 in words is "five trillion, four hundred twenty-five billion, three hundred one million, four hundred fourteen thousand, two hundred fifty-seven".