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5425341415301 = 36131501616777
BaseRepresentation
bin100111011110010111110…
…0011000011111110000101
3201012122202101000202222002
41032330233203003332011
51202342044400242201
615312211211115045
71066653006065333
oct116745743037605
921178671022862
105425341415301
111801968877295
12737573a42a85
133047b88a76b2
1414a8333a6b53
15961d3c7c76b
hex4ef2f8c3f85

5425341415301 has 4 divisors (see below), whose sum is σ = 5426843035692. Its totient is φ = 5423839794912.

The previous prime is 5425341415297. The next prime is 5425341415357. The reversal of 5425341415301 is 1035141435245.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 526312524676 + 4899028890625 = 725474^2 + 2213375^2 .

It is a cyclic number.

It is not a de Polignac number, because 5425341415301 - 22 = 5425341415297 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (5425341415381) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 750804776 + ... + 750812001.

It is an arithmetic number, because the mean of its divisors is an integer number (1356710758923).

Almost surely, 25425341415301 is an apocalyptic number.

It is an amenable number.

5425341415301 is a deficient number, since it is larger than the sum of its proper divisors (1501620391).

5425341415301 is a wasteful number, since it uses less digits than its factorization.

5425341415301 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1501620390.

The product of its (nonzero) digits is 144000, while the sum is 38.

The spelling of 5425341415301 in words is "five trillion, four hundred twenty-five billion, three hundred forty-one million, four hundred fifteen thousand, three hundred one".

Divisors: 1 3613 1501616777 5425341415301