Base | Representation |
---|---|
bin | 110010100100100010… |
… | …001111111000111001 |
3 | 12012011021010021212012 |
4 | 302210202033320321 |
5 | 1342201303031303 |
6 | 40540050255305 |
7 | 3631414541423 |
oct | 624442177071 |
9 | 165137107765 |
10 | 54300048953 |
11 | 21034a64517 |
12 | a634b87535 |
13 | 51748a85a7 |
14 | 28b186b813 |
15 | 162c1385d8 |
hex | ca488fe39 |
54300048953 has 2 divisors, whose sum is σ = 54300048954. Its totient is φ = 54300048952.
The previous prime is 54300048941. The next prime is 54300048989. The reversal of 54300048953 is 35984000345.
54300048953 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 47370651904 + 6929397049 = 217648^2 + 83243^2 .
It is a cyclic number.
It is not a de Polignac number, because 54300048953 - 28 = 54300048697 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 54300048953.
It is not a weakly prime, because it can be changed into another prime (54300048053) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27150024476 + 27150024477.
It is an arithmetic number, because the mean of its divisors is an integer number (27150024477).
Almost surely, 254300048953 is an apocalyptic number.
It is an amenable number.
54300048953 is a deficient number, since it is larger than the sum of its proper divisors (1).
54300048953 is an equidigital number, since it uses as much as digits as its factorization.
54300048953 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 259200, while the sum is 41.
The spelling of 54300048953 in words is "fifty-four billion, three hundred million, forty-eight thousand, nine hundred fifty-three".
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