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5430420131 is a prime number
BaseRepresentation
bin1010000111010110…
…11010001010100011
3112000110021220222112
411003223122022203
542110141421011
62254504425535
7251366544443
oct50353321243
915013256875
105430420131
112337370024
1210767782ab
13687091466
14397304123
1521bb2858b
hex143ada2a3

5430420131 has 2 divisors, whose sum is σ = 5430420132. Its totient is φ = 5430420130.

The previous prime is 5430420119. The next prime is 5430420139. The reversal of 5430420131 is 1310240345.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 5430420131 - 210 = 5430419107 is a prime.

It is a super-2 number, since 2×54304201312 = 58978925598340114322, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 5430420097 and 5430420106.

It is not a weakly prime, because it can be changed into another prime (5430420139) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2715210065 + 2715210066.

It is an arithmetic number, because the mean of its divisors is an integer number (2715210066).

Almost surely, 25430420131 is an apocalyptic number.

5430420131 is a deficient number, since it is larger than the sum of its proper divisors (1).

5430420131 is an equidigital number, since it uses as much as digits as its factorization.

5430420131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1440, while the sum is 23.

The square root of 5430420131 is about 73691.3843742944. The cubic root of 5430420131 is about 1757.6988835293.

Adding to 5430420131 its reverse (1310240345), we get a palindrome (6740660476).

The spelling of 5430420131 in words is "five billion, four hundred thirty million, four hundred twenty thousand, one hundred thirty-one".