Base | Representation |
---|---|
bin | 11000101100101010110000… |
… | …10100110010111010010110 |
3 | 21010022010001220012120002011 |
4 | 30112111120110302322112 |
5 | 24104314112341214332 |
6 | 311302141530534434 |
7 | 14303602501022005 |
oct | 1426253024627226 |
9 | 233263056176064 |
10 | 54311343304342 |
11 | 1633a347446443 |
12 | 6111a9ab9741a |
13 | 243c6cb4252c7 |
14 | d5a97c3a2c3c |
15 | 642b6907ce47 |
hex | 316558532e96 |
54311343304342 has 16 divisors (see below), whose sum is σ = 83598649736112. Its totient is φ = 26447422510080.
The previous prime is 54311343304327. The next prime is 54311343304409. The reversal of 54311343304342 is 24340334311345.
It is a junction number, because it is equal to n+sod(n) for n = 54311343304295 and 54311343304304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 573898488 + ... + 573993115.
It is an arithmetic number, because the mean of its divisors is an integer number (5224915608507).
Almost surely, 254311343304342 is an apocalyptic number.
54311343304342 is a deficient number, since it is larger than the sum of its proper divisors (29287306431770).
54311343304342 is a wasteful number, since it uses less digits than its factorization.
54311343304342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1147892223.
The product of its (nonzero) digits is 622080, while the sum is 40.
Adding to 54311343304342 its reverse (24340334311345), we get a palindrome (78651677615687).
The spelling of 54311343304342 in words is "fifty-four trillion, three hundred eleven billion, three hundred forty-three million, three hundred four thousand, three hundred forty-two".
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