Base | Representation |
---|---|
bin | 110010100101001110… |
… | …000001011111101010 |
3 | 12012012001201022010011 |
4 | 302211032001133222 |
5 | 1342212222234310 |
6 | 40541140242134 |
7 | 3631614224350 |
oct | 624516013752 |
9 | 165161638104 |
10 | 54311524330 |
11 | 210404920a8 |
12 | a6389a034a |
13 | 517709585b |
14 | 28b31b77d0 |
15 | 162d15378a |
hex | ca53817ea |
54311524330 has 16 divisors (see below), whose sum is σ = 111726564480. Its totient is φ = 18621094032.
The previous prime is 54311524327. The next prime is 54311524357. The reversal of 54311524330 is 3342511345.
54311524330 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a junction number, because it is equal to n+sod(n) for n = 54311524292 and 54311524301.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 387939390 + ... + 387939529.
It is an arithmetic number, because the mean of its divisors is an integer number (6982910280).
Almost surely, 254311524330 is an apocalyptic number.
54311524330 is an abundant number, since it is smaller than the sum of its proper divisors (57415040150).
54311524330 is a wasteful number, since it uses less digits than its factorization.
54311524330 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 775878933.
The product of its (nonzero) digits is 21600, while the sum is 31.
The spelling of 54311524330 in words is "fifty-four billion, three hundred eleven million, five hundred twenty-four thousand, three hundred thirty".
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