Base | Representation |
---|---|
bin | 100111100001001000000… |
… | …0000000101001111010011 |
3 | 201020020000110201211011001 |
4 | 1033002100000011033103 |
5 | 1202441202134241312 |
6 | 15315030043202431 |
7 | 1100252360254633 |
oct | 117022000051723 |
9 | 21206013654131 |
10 | 5431254602707 |
11 | 18044226a352a |
12 | 738744216417 |
13 | 30521b99925b |
14 | 14ac348586c3 |
15 | 9642ce68057 |
hex | 4f0900053d3 |
5431254602707 has 2 divisors, whose sum is σ = 5431254602708. Its totient is φ = 5431254602706.
The previous prime is 5431254602699. The next prime is 5431254602789. The reversal of 5431254602707 is 7072064521345.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 5431254602707 - 23 = 5431254602699 is a prime.
It is not a weakly prime, because it can be changed into another prime (5431254602107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2715627301353 + 2715627301354.
It is an arithmetic number, because the mean of its divisors is an integer number (2715627301354).
Almost surely, 25431254602707 is an apocalyptic number.
5431254602707 is a deficient number, since it is larger than the sum of its proper divisors (1).
5431254602707 is an equidigital number, since it uses as much as digits as its factorization.
5431254602707 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1411200, while the sum is 46.
The spelling of 5431254602707 in words is "five trillion, four hundred thirty-one billion, two hundred fifty-four million, six hundred two thousand, seven hundred seven".
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