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54312716639 = 184631294169
BaseRepresentation
bin110010100101010010…
…100100100101011111
312012012010221212122202
4302211102210211133
51342213023413024
640541222002115
73631630321436
oct624522444537
9165163855582
1054312716639
1121041126985
12a63927633b
1351773c246c
1428b340811d
15162d2dbbae
hexca54a495f

54312716639 has 4 divisors (see below), whose sum is σ = 54313195440. Its totient is φ = 54312237840.

The previous prime is 54312716501. The next prime is 54312716651. The reversal of 54312716639 is 93661721345.

54312716639 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a brilliant number, because the two primes have the same length.

It is a cyclic number.

It is not a de Polignac number, because 54312716639 - 232 = 50017749343 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 54312716593 and 54312716602.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (54312718639) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 37547 + ... + 331715.

It is an arithmetic number, because the mean of its divisors is an integer number (13578298860).

Almost surely, 254312716639 is an apocalyptic number.

54312716639 is a deficient number, since it is larger than the sum of its proper divisors (478801).

54312716639 is a wasteful number, since it uses less digits than its factorization.

54312716639 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 478800.

The product of its digits is 816480, while the sum is 47.

The spelling of 54312716639 in words is "fifty-four billion, three hundred twelve million, seven hundred sixteen thousand, six hundred thirty-nine".

Divisors: 1 184631 294169 54312716639