Base | Representation |
---|---|
bin | 100111100001001010111… |
… | …0000010101111111110110 |
3 | 201020020021012101102220000 |
4 | 1033002111300111333312 |
5 | 1202441401342442332 |
6 | 15315043412252130 |
7 | 1100254641646521 |
oct | 117022560257766 |
9 | 21206235342800 |
10 | 5431351140342 |
11 | 180447213a6a6 |
12 | 738770611046 |
13 | 305235999b0a |
14 | 14ac435c7bb8 |
15 | 96436686b7c |
hex | 4f095c15ff6 |
5431351140342 has 40 divisors (see below), whose sum is σ = 12699391080816. Its totient is φ = 1731735145008.
The previous prime is 5431351140287. The next prime is 5431351140409. The reversal of 5431351140342 is 2430411531345.
5431351140342 is a `hidden beast` number, since 5 + 43 + 135 + 1 + 140 + 342 = 666.
It is a super-3 number, since 3×54313511403423 (a number of 39 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5431351140297 and 5431351140306.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 728841033 + ... + 728848484.
Almost surely, 25431351140342 is an apocalyptic number.
5431351140342 is an abundant number, since it is smaller than the sum of its proper divisors (7268039940474).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
5431351140342 is a wasteful number, since it uses less digits than its factorization.
5431351140342 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1457689554 (or 1457689545 counting only the distinct ones).
The product of its (nonzero) digits is 86400, while the sum is 36.
Adding to 5431351140342 its reverse (2430411531345), we get a palindrome (7861762671687).
The spelling of 5431351140342 in words is "five trillion, four hundred thirty-one billion, three hundred fifty-one million, one hundred forty thousand, three hundred forty-two".
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