Base | Representation |
---|---|
bin | 100111100001001110000… |
… | …0010011010101010100001 |
3 | 201020020112112201100212212 |
4 | 1033002130002122222201 |
5 | 1202442110333310340 |
6 | 15315102055331505 |
7 | 1100260361565212 |
oct | 117023402325241 |
9 | 21206475640785 |
10 | 5431456541345 |
11 | 180451668aa6a |
12 | 73879b980b95 |
13 | 305251781a83 |
14 | 14ac535c3409 |
15 | 96440a56a65 |
hex | 4f09c09aaa1 |
5431456541345 has 64 divisors (see below), whose sum is σ = 7154648110080. Its totient is φ = 3944660041728.
The previous prime is 5431456541341. The next prime is 5431456541347.
5431456541345 is nontrivially palindromic in base 10.
It is a cyclic number.
It is not a de Polignac number, because 5431456541345 - 22 = 5431456541341 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 5431456541293 and 5431456541302.
It is not an unprimeable number, because it can be changed into a prime (5431456541341) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 44593649 + ... + 44715281.
It is an arithmetic number, because the mean of its divisors is an integer number (111791376720).
Almost surely, 25431456541345 is an apocalyptic number.
It is an amenable number.
5431456541345 is a deficient number, since it is larger than the sum of its proper divisors (1723191568735).
5431456541345 is a wasteful number, since it uses less digits than its factorization.
5431456541345 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 121914.
The product of its digits is 8640000, while the sum is 50.
The spelling of 5431456541345 in words is "five trillion, four hundred thirty-one billion, four hundred fifty-six million, five hundred forty-one thousand, three hundred forty-five".
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