Base | Representation |
---|---|
bin | 11000101100111011101101… |
… | …00110111010001110101001 |
3 | 21010022222112221200211022121 |
4 | 30112131312212322032221 |
5 | 24104441230433211402 |
6 | 311310244412351241 |
7 | 14304344113524202 |
oct | 1426356646721651 |
9 | 233288487624277 |
10 | 54320441303977 |
11 | 16343195a92202 |
12 | 61137b9a75521 |
13 | 244051b298744 |
14 | d5b1a28085a9 |
15 | 642eecb66837 |
hex | 3167769ba3a9 |
54320441303977 has 2 divisors, whose sum is σ = 54320441303978. Its totient is φ = 54320441303976.
The previous prime is 54320441303873. The next prime is 54320441304037. The reversal of 54320441303977 is 77930314402345.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 48653680097961 + 5666761206016 = 6975219^2 + 2380496^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-54320441303977 is a prime.
It is not a weakly prime, because it can be changed into another prime (54320441303077) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27160220651988 + 27160220651989.
It is an arithmetic number, because the mean of its divisors is an integer number (27160220651989).
Almost surely, 254320441303977 is an apocalyptic number.
It is an amenable number.
54320441303977 is a deficient number, since it is larger than the sum of its proper divisors (1).
54320441303977 is an equidigital number, since it uses as much as digits as its factorization.
54320441303977 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 7620480, while the sum is 52.
The spelling of 54320441303977 in words is "fifty-four trillion, three hundred twenty billion, four hundred forty-one million, three hundred three thousand, nine hundred seventy-seven".
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