Base | Representation |
---|---|
bin | 100111100001100111100… |
… | …1001110111011101101011 |
3 | 201020022202022102111112222 |
4 | 1033003033021313131223 |
5 | 1203000334404213311 |
6 | 15315323132424255 |
7 | 1100320544153402 |
oct | 117031711673553 |
9 | 21208668374488 |
10 | 5432314132331 |
11 | 1804916786849 |
12 | 73899b01808b |
13 | 30535a34a268 |
14 | 14acd5460639 |
15 | 96490ea7adb |
hex | 4f0cf27776b |
5432314132331 has 2 divisors, whose sum is σ = 5432314132332. Its totient is φ = 5432314132330.
The previous prime is 5432314132321. The next prime is 5432314132387. The reversal of 5432314132331 is 1332314132345.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-5432314132331 is a prime.
It is a super-2 number, since 2×54323141323312 (a number of 26 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 5432314132291 and 5432314132300.
It is not a weakly prime, because it can be changed into another prime (5432314132321) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2716157066165 + 2716157066166.
It is an arithmetic number, because the mean of its divisors is an integer number (2716157066166).
Almost surely, 25432314132331 is an apocalyptic number.
5432314132331 is a deficient number, since it is larger than the sum of its proper divisors (1).
5432314132331 is an equidigital number, since it uses as much as digits as its factorization.
5432314132331 is an evil number, because the sum of its binary digits is even.
The product of its digits is 77760, while the sum is 35.
Adding to 5432314132331 its reverse (1332314132345), we get a palindrome (6764628264676).
The spelling of 5432314132331 in words is "five trillion, four hundred thirty-two billion, three hundred fourteen million, one hundred thirty-two thousand, three hundred thirty-one".
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