5433100129 has 2 divisors, whose sum is σ = 5433100130. Its totient is φ = 5433100128.

The previous prime is 5433100097. The next prime is 5433100147. The reversal of 5433100129 is 9210013345.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 3209789025 + 2223311104 = 56655^2 + 47152^2 .

It is a cyclic number.

It is not a de Polignac number, because 5433100129 - 2⁵ = 5433100097 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 5433100097 and 5433100106.

It is not a weakly prime, because it can be changed into another prime (5433100429) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2716550064 + 2716550065.

It is an arithmetic number, because the mean of its divisors is an integer number (2716550065).

Almost surely, 2^5433100129 is an apocalyptic number.

It is an amenable number.

5433100129 is a deficient number, since it is larger than the sum of its proper divisors (1).

5433100129 is an equidigital number, since it uses as much as digits as its factorization.

5433100129 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3240, while the sum is 28.

The square root of 5433100129 is about 73709.5660616721. The cubic root of 5433100129 is about 1757.9879866845.

The spelling of 5433100129 in words is "five billion, four hundred thirty-three million, one hundred thousand, one hundred twenty-nine".